Question

A 10 N horizontal force is applied to a 50 N block initially at rest on...

A 10 N horizontal force is applied to a 50 N block initially at rest on a rough horizontal surface. If the coefficient of static friction is 0.5 and the coefficient of kinetic friction is 0.4, then the frictional force on the block is

A : 10 N

B : 20 N

C : 25 N

D : 0 N

minimum force needed to move the object

F = us * N

F = 0.5* 50

F = 25 N

since the applied force ( = 10 N ) < 25 N

so the object won't move because minimum friciton force is more than apllied force, so actual fricitonal force acting on object will be equal to applied6force

F = 10 N

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Comment in case any doubt, will reply for sure.. Goodluck

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