A 10 N horizontal force is applied to a 50 N block initially at rest on a rough horizontal surface. If the coefficient of static friction is 0.5 and the coefficient of kinetic friction is 0.4, then the frictional force on the block is
A : 10 N
B : 20 N
C : 25 N
D : 0 N
minimum force needed to move the object
F = us * N
F = 0.5* 50
F = 25 N
since the applied force ( = 10 N ) < 25 N
so the object won't move because minimum friciton force is more than apllied force, so actual fricitonal force acting on object will be equal to applied6force
F = 10 N
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Comment in case any doubt, will reply for sure.. Goodluck
A 10 N horizontal force is applied to a 50 N block initially at rest on...
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