When a 310-g piece of iron at 180 ∘C is placed in a 95-g aluminum calorimeter cup containing 250 g of liquid at 10∘C, the final temperature is observed to be 37 ∘C. The value of specific heat for iron is 450 J/kg⋅C∘, and for aluminum is 900 J/kg⋅C∘. Part A Determine the specific heat of the liquid. Express your answer using two significant figures. c c = nothing Jkg⋅C∘ Request Answer
Solution,
Q = m c dT
m_{I} c_{i} Ti = m_{a} c_{a} T_{a} + m_{w} c_{w} T_{w}
0.310 x 450 x 143 = 0.095 x 900 x 27 + 0.250 x C_{w} x 27
C_{w} = 2613.33 J/kg
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When a 310-g piece of iron at 180 ∘C is placed in a 95-g aluminum calorimeter...
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