Sketch CpRe(Br)2(PMe3). Assign the oxidation state, d-count, and 18e- count. Is it likely to react via...
Sketch CpRe(Br)2(PMe3). Assign the oxidation state, d-count, and 18e- count. Is it likely to react via associative or dissociative substitution in a non-polar solvent if the incoming ligand is CNMe (methyl isocyanide)? Why?
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Sketch CpRe(Br)2(PMe3). Assign the oxidation state, d-count, and
18e- count. Is it likely to react via...
1. In both the sodium iodide test and the silver nitrate test, why does 2-bromobutane react faster...
1. In both the sodium iodide
test and the silver nitrate test, why does 2-bromobutane react
faster than 2-chlorobutane?
Bromine is a better leaving group since it is a weaker base than
chlorine is.
2. a. Why does benzyl chloride react under both
SN1 and SN2 conditions?
Benzyl
chloride is a primary alkyl halide, hence reactive under SN2
conditions.
The
primary carbocation formed due to the departure of Cl- is
stabilized by the pi electrons in the benzene ring.
b. Why is...
1. In both the sodium iodide
test and the silver nitrate test, why does 2-bromobutane react
faster than 2-chlorobutane?
Bromine is a better leaving group since it is a weaker base than
chlorine is.
2. a. Why does benzyl chloride react under both
SN1 and SN2 conditions?
Benzyl
chloride is a primary alkyl halide, hence reactive under SN2
conditions.
The
primary carbocation formed due to the departure of Cl- is
stabilized by the pi electrons in the benzene ring.
b. Why is...
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