Question

I need a simple explanation of WHY the output is what it is -- Unix/Linux shell programming I am taking this introductory course in college

echo * CIS132 **

echo "\\"

echo $t1 variable t1=$t{1}\!\\n

echo -e $t1 variable t1=$t{1}\!\\n

Thanks for the explanations.

Answer 1

PLEASE FIND THE ANSWERS BELOW.

  

1. echo *CIS132**
   • It will print *CIS132** because whatever STRING we write after echo, it will display it.
2. echo "\\"
   • It will print \ because \ (forward slash) is an escape sequence character. If we want to output a single forward slash, we use \\ to print it.
3. echo $t1 variable t1=$t{1}\!\\n
   • It will print echo $t1 variable t1=$t{1}!\n
   • Reason:
     • There is no -e. So, it will print the string it was given.
     • As discussed above to print a special character, we use / before it. There is a / before /n . Hence, it prints \n
4. echo -e $t1 variable t1=$t{1}\!\\n
   • It will print echo $t1 variable t1=$t{1}!
   • Reason:
     • ​​​​​​​-e option will interpret the \n as new line. So, it prints a new line after the output.

The outputs are given below: