A 1,200-kg car is traveling on an icy horizontal road at 30 m/s. The maximum rate at which the car can decelerate without sliding on the ice is 1.2 m/s2; reaching this value will immediately result in sliding uncontrollably with a reduced sliding friction of 700 N.
If the driver panics and slams hard on the brakes, then how far will the car slide before stopping? Answer in km.
friction = 700 N
deceleration = F/m = 700 / 1200 = 0.5833 m/s^2
using the equation of linear motion we have
v^2 - u^2 = 2aS
0 - 30^2 = 2*-0.5833*S
S = 771.4 m
so the car slides 771.4 m
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