In the preparation of a dosage form of a drug, 1.100 L of a 0.0001700 M solution of an excipient (MW = 140.1) is needed. A 0.3780 mg/mL standard solution of the excipient is available. How much of the standard solution is required to prepare the 0.0001700 M solution?
standard solution = 0.3780 mg / mL
= 0.3780 x 10^-3 g / 10^-3 L
= 0.3780 g / L
= ( 0.3780 g / L ) / (140.1 g / mole )
= 2.70 x 10^-3 mol / L
molarity of stock solution = 2.70 x 10^-3 M = C1
C1 V1 = C2 V2
2.70 x 10^-3 x V1 = 0.0001700 x 1.100
V1 = 0.0693 L
volume of stock solution needed = 0.0693 L
In the preparation of a dosage form of a drug, 1.100 L of a 0.0001700 M...
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