Question

Given the class below, which answer choice would be an implementation of the parameterized constructor (without an initialization list)?

class MyInteger {
    private:
       int num;
    public:
       MyInteger();
       MyInteger(int newint);
       void setInt(int newint);
       int getInt();
       int operator[](int index);
};

  

MyInteger::MyInteger(newNum) { num = newNum; }

   

MyInteger::MyInteger(int newNum) { num = newNum; }

   

Integer::MyInteger(int newNum = 0) : num{0} {;}

   

MyInteger::MyInteger(int newNum) : num{0} {;}

   

MyInteger::MyInteger() { num = 0; }

   

MyInteger::MyInteger() : num{0} {;}

   

MyInteger::MyInteger(int newNum = 0) { num = newNum; }

Answer 1

MyInteger::MyInteger(newNum) { num = newNum; }
incorrect because input parameter format/syntax is incorrect

MyInteger::MyInteger(int newNum) { num = newNum; }
this is correct

Integer::MyInteger(int newNum = 0) : num{0} {;}
incorrect because it's using initialization list

MyInteger::MyInteger(int newNum) : num{0} {;}
incorrect because it's using initialization list

MyInteger::MyInteger() { num = 0; }
incorrect because it's default constructor

MyInteger::MyInteger() : num{0} {;}
incorrect because it's default constructor

MyInteger::MyInteger(int newNum = 0) { num = newNum; }
incorrect because we can't use default parameters (= 0) in member function definitions. we must put it in declaration.

Answer:
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b)  MyInteger::MyInteger(int newNum) { num = newNum; }