Question

You are on an engineering team examining the feasibility of a satellite launching system that uses...

You are on an engineering team examining the feasibility of a satellite launching system that uses the electric force instead of rocket fuel. The proposed launching system consists of 4 metal spheres, each one 15 m above the ground, arranged at the corners of a square with sides 5 meters long. The satellite is placed on the ground below the center of the square. To launch the satellite, the four spheres are first each given a charge of +Q/4 and the satellite is given a charge –Q. The satellite is then released and is pulled straight upward through the center of the square.

When the satellite reaches 15 m above the ground (the same height as the spheres), the spheres are neutralized. To evaluate this idea, you decide to calculate how big Q would have to be to launch a 100 kg satellite at a speed of 8 km/s. You are also worried about dielectric breakdown of the air, which causes spontaneous sparking in the presence of electric fields larger than 3 x 106 V/m and so decide to check whether that will be a problem. For this purpose, you assume that the spheres have a diameter of 1 m.

(a) Give a purely symbolic answer to the problem in terms of (only) the quantities given in the problem and known constants. Be sure to define each of the symbols you use.
(b) Give a numerical answer to the problem.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

(a) we know that the electrostatic potential energy between the charges q 1 and q 2 placed at r distance apart is given by

In the above figure, OC = and AC = = 15.411 m (by pythagorean theorem)

For position of satellite just below 15 m from the square and spheres is given by

-----------(1)

and for position of satellite just on the level of square and spheres is given by

-------------(2)

Let ,the velocity of satellite is v;then by conservation of energy,

----------------(3)

The electrostatic field at the center of sphere is not greater than

The electrostatic field at the center of sphere is   

By equations (1),(2) and (3),we get

(b)given v = 8 km/s = 8000 m/s, m = 100 kg

Q = 31978.466 C

Add a comment
Know the answer?
Add Answer to:
You are on an engineering team examining the feasibility of a satellite launching system that uses...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • NASA has asked your team of rocket scientists about the feasibility of a new satellite launcher...

    NASA has asked your team of rocket scientists about the feasibility of a new satellite launcher that will save rocket fuel. NASA's idea is basically an electric slingshot that consists of 4 electrodes arranged in a horizontal square 5 m on a side. The satellite is placed 15 m directly under the center of the square. A power supply will provide each of the four electrodes with the same charge and the satellite with an opposite charge 4 times larger....

  • The Space X engineering group has been asked to design a mission to send a satellite...

    The Space X engineering group has been asked to design a mission to send a satellite in orbit around the Earth. The satellite has a mass m_s = 500 kg, and the rocket has a mass m_R = 2000 kg. The satellite is required to revolve with an elliptic orbit around the Earth with velocity v_B = 25 km/s when it is located in point B, at a distance to the earth r_B = 10 Mm. Assuming the mass of...

  • Electric potential for a continuous charge distribution: Let's consider a line of charge, of length L...

    Electric potential for a continuous charge distribution: Let's consider a line of charge, of length L having a uniform charge density lambda = 10^-6 C/m and length L=10 cm. Find the electric potential at point P, which is at a distance Z=5 cm. above the midpoint of the line. where In is the natural logarithm. Consider two charged conducting spheres, radii r1 and r2, with charges q1 and q2, respectively. The spheres are far away from each other but connected...

  • Now we consider a black hole of the same mass as the Sun: Mbh 2 x 1050 k (a) (2 marks) Show that if you are launching a...

    Now we consider a black hole of the same mass as the Sun: Mbh 2 x 1050 k (a) (2 marks) Show that if you are launching a rocket with velocity v upwards from a planet of mass M, you can only escape the planet's gravity if you start from a radius r > 2GM/v2 Hint: Use Newtonian mechanics What if your rocket is acutally a beam of light? If we forget about relativity for a minute, we can put...

  • Now we consider a black hole of the same mass as the Sun: Mbh 2x 1030 kg. (a) (2 marks) Show that if you are launching...

    Now we consider a black hole of the same mass as the Sun: Mbh 2x 1030 kg. (a) (2 marks) Show that if you are launching a rocket with velocity v upwards from a pl M, you can only escape the planet's gravity if you start from a radius r > 2GM/ t of mass Hint: Use Newtonian mechanics. What if your rocket is acutally a beam of light? If we forget about relativity for a minute, we can put...

  • Solve problem 2 and 3 with details . Thank you Notre Dame University-Louaize Faculty of Natural& Applied Sciences Department of Physics& Astronomy PHS 212-Electridity & Magnetism Fall 201...

    Solve problem 2 and 3 with details . Thank you Notre Dame University-Louaize Faculty of Natural& Applied Sciences Department of Physics& Astronomy PHS 212-Electridity & Magnetism Fall 2018 Final Exam (22Dec18, 120min) Closed-book, Closed-notes, Close-everything Exam List in detail any assumptions that you make. Show all your work. You can use a calcalater Useful Constants: e1.6x 10C, charge of 1 electron k-8.9875x10 Nm/C2 mass of 1 electron: 9.11 x 10 kg 1. Three point charges, q +15 C, q +35...

  • Situation 1: You have a metal cube, measuring L on each side. The metal is in electrostatic equil...

    Situation 1: You have a metal cube, measuring L on each side. The metal is in electrostatic equilibrium and has a net 4. charge of Q,. The cube has a cavity within it, however-where there is no metal. The shape of this cavity is not known. Somewhere within the cavity rests a point charge, q,. Its exact location is unknown, but it is not in contact with the inner wall of the cavity At a certain point P, on the...

  • Can someone please help me with part A and B. Thank you (10%) Problem 7: A...

    Can someone please help me with part A and B. Thank you (10%) Problem 7: A conducting sphere of radius r! = 0.31 m has a total charge of Q = 2.3 μC. A new uncharged conducting sphere of radius r2 0.21 m joins to the original by a small conducting wire. The spheres are separated by an immense distance compared to their size - 50% Part (a) what is the total charge on sphere two Q2 after they are...

  • Can you Solve Part b and c and d. ) PM (11%) Problem 7: A hollow...

    Can you Solve Part b and c and d. ) PM (11%) Problem 7: A hollow non-conducting spherical shell has inner radius R1 6 cm and outer radius R2- 19 cm. A charge Q- -25 nC lies at the center of the shell. The shel carries a spherically symmetric charge density o Ar for Rr< R2 that increases linearly with radius, where A-16 μC/m Ctheexpertta.com e 25% Part (a) Write an equation for the radial electric field in the region...

  • Dr. C. #2. (PHYS 121 engineering design exercise) You have seen why cars inherently accelerate qu...

    Dr. C. #2. (PHYS 121 engineering design exercise) You have seen why cars inherently accelerate quicker in a straight line and have better fuel mileage than an SUV with the same engine; it's because of air drag and the smaller frontal area and better drag coefficient of the car. Now let's think about why cars handle (take turns, change lanes and make other quick maneuvers) better than an SUV. We'l1 simplify our analysis by considering a vehicle of mass M...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT