0.02 g (=20 mg) of MgF2(s) is added into 1.0 L of pure water containing no...

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0.02 g (=20 mg) of MgF2(s) is added into 1.0 L of pure water containing no...

0.02 g (=20 mg) of MgF2(s) is added into 1.0 L of pure water containing no Mg 2+ and F- MgF2(S) ↔ Mg2+ + 2F-

Ksp= 3.7 x 10^-11 (AW: Mg=24, F=19)

(a) What would be the concentration (in M) of F- in solution at equilibrium?

(b) How much solid (if any) would remain (in mg/L) after the system reaches

equilibrium?

science chemistry

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