When 2.00 mol of SO2Cl2 is placed in a 2.00-L flask at 302 K , 58...

Question

Question

When 2.00 mol of SO2Cl2 is placed in a 2.00-L flask at 302 K , 58 % of the SO2Cl2 decomposes to SO2 and Cl2:
SO2Cl2(g)⇌SO2(g)+Cl2(g)

B) Calculate Kc for 2.00 mol of SO2Cl2 in a 13.00 −L vessel at 302 K .

Express your answer to two significant figures.

science chemistry

Answer 1

Answer #1

SO2Cl2 molarity = 2/2 =1

SO2Cl2 (g) <----------------------> SO2 (g) + Cl2 (g)

1 0 0 ----------------------initial

1-x x x -------------------------------equilibrium

1-0.58 0.568 0.58

0.42 0.58 0.58

decomposition

x = 58 %

= 58/100

= 0.58

Kc = [SO2][SO2]/ [SO2Cl2]

Kc = 0.58 x 0.58 / 0.42

Kc = 0.801

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Answer 2

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