You try and whirl a 1.0 kg mass on a 1.0 meter long string, at constant speed in a horizontal circle. However, you find that the string is at an angle of 37 degrees below the horizontal because of gravity. How fast is the mass moving in m/s?

From the figure, radius of circle is
, length of string is
,
Net force acting on the mass in the vertical direction is zero,

Net force acting on the mass in the horizontal direction is



Speed of mass is 
You try and whirl a 1.0 kg mass on a 1.0 meter long string, at constant...
A ball of mass 1.25 kg is attached by a 1.4 meter long massless
rope to the top of a vertical pole. The ball swings in a horizontal
circle at a constant rate of ? rad/s with the rope making
an angle of 29
A ball of mass 1.25 kg is attached by a 1.4 meter long massless rope to the top of a vertical pole. The ball swings in a horizontal circle at a constant rate of ? rad/s...
A 1.0-kg ball on the end of a string is whirled at a constant speed of 2.0 m/s in a horizontal circle of radius 1.5 m. What is the work done by the centripetalforce during one half revolution?
Can you please solve? The correct answer is sqrt(4gR) You whirl a ball of mass m in a fast vertical circle on the end of a light string of length R. At the bottom of the circle, the tension in the string is five times the ball's weight. The ball's speed at this point is given by....? Can you draw the free body diagram in your explanation and fully explain how to find tension?
A mass m = 4.700 kg is suspended from a string of length L = 1.270 m. It revolves in a horizontal circle. The tangential speed of the mass is 2.243 m/s. What is the angle theta between the string and the vertical (in degrees)?
A mass m = 8.3 kg is suspended from a string of length L = 1.33 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 3.27 m/s. What is the angle between the string and the vertical (in degrees)?
A mass m = 4.300 kg is suspended from a string of
length L = 1.290 m. It revolves in a horizontal circle
(see Figure). The tangential speed of the mass is 3.743
m/s. What is the angle theta between the string and the
vertical (in degrees)?
A mass m = 7.9 kg is suspended from a string of length L = 1.15 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 2.80 m/s. What is the angle θ between the string and the vertical (in degrees)?
A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V. The string maintains a constant angle 0 = 44.1 degrees with the vertical line through the pivot point as it swings. What is the speed V required to make this motion possible?
A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V. The string maintains a constant angle theta θ= 46.5 degrees with the vertical line through the pivot point as it swings. What is the speed V required to make this motion possible?
This mass (m) on a string (of length L) is moving in a horizontal circle. The string makes an angle of 60 degrees with the vertical. (Express your answers in terms of m, L, g, and theta) Find the tension in the string. Find the speed of the mass.