Assume that you want to construct a 95% confidence interval estimate of a population mean. Find...
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error equals=$66, standard deviation equals=$2222
The required sample size is _____. (Round up to the nearest whole number as needed.)
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Assume that you want to construct a 95% confidence interval
estimate of a population mean. Find...
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find...
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error =$5,standard deviation=$25 The required sample size is ????? (Round up to the nearest whole number as needed.)
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find...
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of errorequals $3, standard deviationequals $23 The required sample size is nothing . (Round up to the nearest whole number as needed.)
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find...
Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given below. Margin of error equals$5, standard deviation equals$19 The required sample size is __.
Determine the sample size needed to construct a 95% confidence interval to estimate the average GPA...
Determine the sample size needed to construct a 95% confidence interval to estimate the average GPA for the student population at a college with a margin of error equal to 0.2. Assume the standard deviation of the GPA for the student population is 25 The sample size needed is (Round up to the nearest integer.) Determine the sample size n needed to construct a 90% confidence interval to estimate the population proportion for the following sample proportions when the margin...
Determine the sample sizen needed to construct a 95% confidence interval to estimate the population proportion...
Determine the sample sizen needed to construct a 95% confidence interval to estimate the population proportion for the following sample proportions when the margin of error equals 5% . a.p 0.70 b. p 0 80 c.p 0 90 Click the icon to view a table of standard normal cumulative probabilties a, nm (Round up to the nearest integer)
Determine the sample sizen needed to construct a 95% confidence interval to estimate the population proportion for the following sample proportions when...
Determine the sample size n needed to construct a 95% confidence interval to estimate the population...
Determine the sample size n needed to construct a 95% confidence interval to estimate the population mean when sigma equals 49 and the margin of error equals 6. n=????
8.2.29 Question Help A manager wishes to estimate a population mean using a 95% confidence interval...
8.2.29 Question Help A manager wishes to estimate a population mean using a 95% confidence interval estimate that has a margin of error of +49.0. If the population standard deviation is thought to be 680, what is the required sample size? The sample size must be at least (Round up to the nearest whole number.)
Find the margin of error for a 95% confidence interval for estimating the population mean when...
Find the margin of error for a 95% confidence interval for estimating the population mean when the sample standard deviation equals 92, with a sample size of (a) 400,(b) 1800. What is the effect of the sample size? 2. The margin of error for a 95% confidence interval with a sample size of 400 is (Round to the nearest tenth as needed.) b. The margin of error for a 90% confidence interval with a sample size of 1600 is (Round...
8.1.5 Question Help Determine the 95% confidence interval estimate for the population mean of a normal...
8.1.5 Question Help Determine the 95% confidence interval estimate for the population mean of a normal distribution given n = 100, o = 133, and x = 1,500 The 95% confidence interval for the population mean is from to (Round to two decimal places as needed. Use ascending order.) 8.1.14-T Question Help As a follow-up to a report on gas consumption, a consumer group conducted a study of SUV owners to estimate the mean mileage for their vehicles. A simple...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a random sample of 32 computers, the mean repair cost was $143 with a sample standard deviation of $35 (Section 6.2) Margin of error, E. <με. Confidence Interval: O Suppose you did some research on repair costs for computers and found that the population standard deviation, a,- $35. Use the normal distribution to construct a 95% confidence interval the population mean, u. Compare the results....
Determine the sample size needed to construct a 95% confidence interval to estimate the average GPA for the student population at a college with a margin of error equal to 0.2. Assume the standard deviation of the GPA for the student population is 25 The sample size needed is (Round up to the nearest integer.) Determine the sample size n needed to construct a 90% confidence interval to estimate the population proportion for the following sample proportions when the margin...
Determine the sample sizen needed to construct a 95% confidence interval to estimate the population proportion for the following sample proportions when the margin of error equals 5% . a.p 0.70 b. p 0 80 c.p 0 90 Click the icon to view a table of standard normal cumulative probabilties a, nm (Round up to the nearest integer)
Determine the sample sizen needed to construct a 95% confidence interval to estimate the population proportion for the following sample proportions when...
8.2.29 Question Help A manager wishes to estimate a population mean using a 95% confidence interval estimate that has a margin of error of +49.0. If the population standard deviation is thought to be 680, what is the required sample size? The sample size must be at least (Round up to the nearest whole number.)
Find the margin of error for a 95% confidence interval for estimating the population mean when the sample standard deviation equals 92, with a sample size of (a) 400,(b) 1800. What is the effect of the sample size? 2. The margin of error for a 95% confidence interval with a sample size of 400 is (Round to the nearest tenth as needed.) b. The margin of error for a 90% confidence interval with a sample size of 1600 is (Round...
8.1.5 Question Help Determine the 95% confidence interval estimate for the population mean of a normal distribution given n = 100, o = 133, and x = 1,500 The 95% confidence interval for the population mean is from to (Round to two decimal places as needed. Use ascending order.) 8.1.14-T Question Help As a follow-up to a report on gas consumption, a consumer group conducted a study of SUV owners to estimate the mean mileage for their vehicles. A simple...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a random sample of 32 computers, the mean repair cost was $143 with a sample standard deviation of $35 (Section 6.2) Margin of error, E. <με. Confidence Interval: O Suppose you did some research on repair costs for computers and found that the population standard deviation, a,- $35. Use the normal distribution to construct a 95% confidence interval the population mean, u. Compare the results....
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