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You draw two balls from the urn but do not replace the first ball before drawing...

You draw two balls from the urn but do not replace the first ball before drawing the second. An urn contains 12 balls identical in every respect except color. There are 3 red balls, 7 green balls, and 2 blue balls. Find the probability that the first ball is red and the second is green. Write your answer as a decimal to the nearest thousandths place (0.XXX).

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Answer #1

Here n(r) = 3, n(g) = 7 , n(b) = 2

So, p(1st red and 2nd green) = 3/12×7/11

= 21/132=0.159

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