Question 45
Given that the probability of a family owning a dog is 0.91, and the probability of a family owning a cat and a dog is 0.15, what is the probability of a family owning a cat given that the family owns a dog?
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Question 45 Given that the probability of a family owning a dog is 0.91, and the...
GHIJKLM Sup, use the probability of a person owning a pet is independent and the probability a person owns a cat is 32% and the probability of a person owning a dog is 28%. The probability of a person owning both a cat and a dog is 15%. a. Find the probability of a person having a cat or a dog. answer: b. Find the probability of a person having neither a cat nor a dog. answer: C. Suppose you...
In a certain community, 35% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known that 32% of all the families own a cat. What is the probability that a randomly selected family owns a dog? What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
Question 3 The average yearly cost per household of owning a dog is $186.80. Suppose that we randomly select 50 households that own a dog. Assume o = $32.00. What is the probability that the sample mean for these 50 households is between $195 and $200?
A dog walking to the right at 1.5m/s spies a cat ahead, and begins chasing the cat with a constant acceleration of 12 m/s. What is the velocity of the dog after running for 3.0 m? Round the answer to two significant digits. Answer using a coordinate system where rightward is positive.
a) Suppose one injured individual is selected at random. What is the probability that this person is 75-or-over and experienced a dog-related injury? b) Suppose one injured individual is selected at random. What is the probability that this person is between 55 and 74 years old? c) Suppose one injured individual is selected at random. What is the probability that this individual is at least 55 years old (i.e., is 55 years old or older)? d) Suppose one injured person...
The probability that concert tickets are available by telephone is 0.91. For the same event, the probability that tickets are available through a Web site is 0.95. Assume that these two ways to buy tickets are independent. What is the probability that someone who tries to buy tickets both through the Internet and by the telephone will obtain at least one ticket? Round your answer to four decimal places (e.g. 98.7654)
Question 3: My dog Peter lies to lick Jack, his cat companion. Because Jack prefers not to be Ecked by a slobbery dog, be tries to dodge Peter's tongue, so that the licks only hit their intended arget with probability 0.7, independently. One afternoon, Peter aims 8 licks at the cat. (a) (5 pts) What is the probability that Peter lands exactly 4 licks on Jack? (b) (10 pts) Given that he lands at least two licks, what is the...
A rare autosomal dominant condition affects the following family pedigree. What is the probability that the unborn child marked with the question mark is affected by the condition? Express the answer as a decimal fraction with two digits after the decimal point. Do not round the fraction. (i.e 1/3 = 0.33) Answer:
3 Question 6 (8 points) A dog is chasing a cat, which is chasing a mouse. All of the animals are moving in one dimension. The mouse is in the lead, moving at 4.31 m/s. The cat is in the middle, moving at 1.12 m/s. The dog is in the back, moving at 4.26 m/s. All velocities are relative to the ground. What is the velocity of the cat from the perspective of the dog? Include negative signs as appropriate....
a) The probability that a randomly selected household has one cat is (Simplify your answer.) b) The probability that a randomly selected family has more than one cat is (Simplify your answer.) A survey was conducted in which 125 families were asked how many cats lived in their households. The results are shown below. a) What is the probability that a randomly selected family has one cat? b) What is the probability that a randomly selected family has more than...