Question

True or False? A researcher wants to estimate the impact prenatal care during pregnancy can have on premature deliveries by conducting a retrospective case-control study on new moms. If the prevalence of premature births is approximately 10.9%, the researcher should enroll a total of 586 women in the study if the researcher wants to construct a 90% confidence interval for the difference in proportions that has a margin of error of no more than 3%. Please show the calculations for 586 women in the study. Thank you!

Answer 1

Given that, n = 586 and sample proportion = 0.109

A 90% confidence level has significance level of 0.10 and critical value is,

The margin of error (E) is,

Therefore, margin of error is 2.12%

Answer : False