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γ-Al2O3 (s) +3H20 (l) + 6H3O+ (aq) -> 2(Al(OH2)6)3+ a.) Use one mole of the product...

γ-Al2O3 (s) +3H20 (l) + 6H3O+ (aq) -> 2(Al(OH2)6)3+

a.) Use one mole of the product above as the reactant in the reaction below. Fill in the reactant and one of the product on the reaction below.

_______________________________ -> H+ (aq) + __________________________________

b.) Use two moles of the non- H+ product in the reaction above an complete the equilibrium reaction below.

2_________________________ <------> _______________________________+ 2H20 (l).

c.) This type of reaction is an ____________________.

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Answer #1

a)

[Al(OH2)6]3+..................> H+ (aq) + [Al(H2O)5(OH)]2+ (aq)

b) 2 [Al(H2O)5(OH)]2+ (aq) <.....................> [Al2(OH)2(H2O)8]4+ + 2 H20 (l).

c) ) This type of reaction is an hydrolysis reaction.

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