Question

can some one help me solve this and explain it please

Input Format

A line indicating the size of the array the array on the next line

Constraints

n < 10000

Output Format

One line printing the array in order input (given to you) One line printing the array, followed by its maximum value

Sample Input 0

5
1 3 5 7 9

Sample Output 0

1 3 5 7 9
9 7 5 3 1 9

Contest ends in 29 minutes

Submissions:

0

Max Score:

50

Difficulty:

Medium

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Current Buffer (saved locally, editable)     

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {
public static void main(String[] args) throws IOException {
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

int n = Integer.parseInt(bufferedReader.readLine().trim());

String[] myArrayTemp = bufferedReader.readLine().replaceAll("\\s+$", "").split(" ");

List<Integer> myArray = new ArrayList<>();

for (int i = 0; i < n; i++) {
int myArrayItem = Integer.parseInt(myArrayTemp[i]);
myArray.add(myArrayItem);
}

for (int i = 0; i < myArray.size(); i++) {
System.out.print(myArray.get(i));

if (i != myArray.size() - 1) {
System.out.print(" ");
}
}

System.out.println();

// You will now have to print the array in reverse, along with the largest value, on the SAME LINE

// Write your code here

bufferedReader.close();
}
}

Answer 1

Hey, I do believe the question is asking something different than what you mentioned in comments; I solved the question according to Output format.

******************************************************************************************************

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
import java.util.Arrays;
import java.util.Collections;

public class Solution {
public static void main(String[] args) throws IOException {
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

int n = Integer.parseInt(bufferedReader.readLine().trim());

String[] myArrayTemp = bufferedReader.readLine().replaceAll("\\s+$", "").split(" ");

List<Integer> myArray = new ArrayList<>();

for (int i = 0; i < n; i++) {
int myArrayItem = Integer.parseInt(myArrayTemp[i]);
myArray.add(myArrayItem);
}

for (int i = 0; i < myArray.size(); i++) {
System.out.print(myArray.get(i));

if (i != myArray.size() - 1) {
System.out.print(" ");
}
}

System.out.println();

// You will now have to print the array in reverse, along with the largest value, on the SAME LINE

// Write your code here

Arrays.sort(myArrayItem);
for (int i = 0; i < myArray.size(); i++) {
System.out.print(myArray.get(i));
System.out.print(" ");
}
int max = Collections.max(Arrays.asList(myArrayItem));
System.out.println(max);
bufferedReader.close();
}
}

******************************************************************************************************************