Find the magnitude of the wave vector of a free electron that has the same energy as a photon with wavelength 550mm.
Wave vector it's magnitude is defined as wave number.
Energy of photon=hc/LAMDA = 1.24/550000= 2.254*10^(-6)ev
Wave no magnitude=wave number = 2π/LAMDA =2π/.550 =11.42
Find the magnitude of the wave vector of a free electron that has the same energy...
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8. Find the kinetic energy of an electron whose de Broglie wave- length is the same as that of a 100-keV x-ray. 9. Green light has a wavelength of about 550 nm Through what
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A photon of wavelength 0.04400 nm strikes a free
electron and is scattered at an angle of 36.0 ∘ from its original
direction.
Find the change in energy of the photon. ΑΣ eV Find the energy gained by the electron. eV
Find the change in energy of the photon. ΑΣ eV
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