an equilibrium mixture is analyzed and found to contain 0.94M N2 , 0.701M H2 and .35...
Homework Answers
A)
Kc = [NH3]^2 / [N2][H2]^3
= (0.35)^2 / (0.94)*(0.701)^3
= 0.378
Answer: 0.378
B)
T= 25.0 oC
= (25.0+273) K
= 298 K
Δ n = number of gaseous molecule in product - number of gaseous molecule in reactant
Δ n = -2
use:
Kp= Kc (RT)^Δ n
Kp = 0.378*(0.08206*298.0)^(-2)
Kp = 6.321*10^-4
Answer: 6.32*10^-4
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