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1. A ball rolls off a track at a height 2.02 meters above the ground, its...

1. A ball rolls off a track at a height 2.02 meters above the ground, its exit velocity is 1.28 m/s at an angle 19.3 degrees below horizontal, how long is its flight time in seconds?

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Answer #1

The initial vertical velocity of the ball in downward direction is

acceleration in downward direction is

Distance travelled in downward direction is given by

Solving above quadratic equation we get

and

We are solving for a positive value of time.

So the flight time is t = 0.6 s.

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