In order for a new drug to be sold on the market, the variance of the active ingredient in each dose should be 0.02mg. A random sample of 25 tablets with a dosage strength of 48.42mg is taken. The variance of the active ingredient from this sample is found to be 0.0048. Does the data suggests at α=0.01 that the variance of the drug in the tablets is less than the desired amount? Assume the population is normally distributed.
Step 1 of 5 :
State the null and alternative hypotheses. Round to four decimal places when necessary
step 2 of 4: Compute the value of the test statistic. Round your answer to two decimal places.
Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H0. Round the numerical portion of your answer to three decimal places.
Step 4 of 4: Make the decision for the hypothesis test. Reject or Fail to Reject Null Hypothesis
step 1
To Test :-
H0 :-
H1 :-
Step 2
Test Statistic :-
χ^{2} = ( ( 25-1 ) * 0.0048 ) / 0.02
χ^{2} = 5.76
Step 3
Test Criteria :-
Reject null hypothesis if
= 10.856
Step 4
= 5.76 < 10.856 , hence we reject the null hypothesis
Conclusion :- We Reject null hypothesis.
In order for a new drug to be sold on the market, the variance of the...
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