Calculate the ΔG°rxn at 298 K using the following information. 2 HNO3(aq) + NO(g) → 3...

Question

Question

Calculate the ΔG°rxn at 298 K using the following information.

2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l) ΔG°rxn = ?

ΔH°f (kJ/mol) -207.0 91.3 33.2 -285.8

S°(J/mol∙K 146.0 210.8 240.1 70.0

science chemistry

Answer 1

Answer #1

2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l)

ΔH°rxn = ΔH°f products - ΔH°f reactants

= (-285.8 + 3*33.2) - (2*-207 + 91.3)

= 136.5 KJ/mole

ΔS°rxn = S°f products - S°f reactants

= 70 + 3*240.1 -(2*146+210.8)

= 287.5J/mole-K = 0.2875Kj/mole-K

ΔG°rxn = ΔH°rxn- TΔS°rxn

= 136.5 - 298*0.2875 = 50.825 KJ/mole

2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l) ΔG°rxn = 50.825 KJ/mole

Answer 2

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