600.0 mL of air is at 20.0 °C. What is the volume at 60.0 °C?

Question

Question

science chemistry

Answer 1

Answer #1

According to Charles's Law, the equation is as

V₁/T₁ = V₂/T₂

V₁ = 600.0 mL ; V₂ = ?

T₁ = 273 + 20 = 293 K

T₂ = 273 + 60 = 333 K

(600.0 mL)/(293 K) = V₂/(333 K)

V₂ = (333 K)(600.0 mL)/(293 K) = 681.9 mL

Answer 2

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