Question

A bag contains 9 white counters, 6 black counters, and 7 green counters. What is the probability of drawing

(a) a white counter or a green counter?

   

(b) a black counter or a green counter?

   

(c) not a green counter?

Answer 1

Total counters = 9 + 6 + 7 = 22

P(White) = 9/22 , P(black) = 6 / 22 , P(green) = 7 / 22

a)

P(White OR green) = P(White) + P(Green)

= 9/22 + 7/22

= 8/11

b)

P(Black OR Green) = P(Black) + P(Green)

= 6/22 + 7/22

= 13/22

c)

P(NOT green) = 1 - P(Green)

= 1 - 7/22

= 15/22