Energy change is the sum of heat and work: ΔE = q + w. Work is...
Energy change is the sum of heat and work: ΔE = q + w. Work is calculated by: w = -PΔV
What is the change in energy (in joules) if a reaction absorbs 72.8 J of heat and increases in volume from 0.250L to 0.750L at a constant pressure of 1.168 atm? Please include the correct sign with your numerical result.
(Note: Make sure your units are consistent when combining energy terms. The conversion factor you need is: 1 L·atm = 101.3 J)
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answerI need help setting up this problem and identifying the variables Energy change is the sum...
I need help setting up this problem and identifying the variables Energy change is the sum of heat and work: ΔE = q + w. Work is calculated by: w = -PΔV What is the change in energy (in joules) if a reaction loses 215 J of heat and decreases in volume from 0.650 L to 0.225 L at a constant pressure of 3.17 atm? Please include the correct sign with your numerical result.
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