Question

Fix this code so only the function prototype comes before main.

#include <iostream>
using namespace std;

bool isMultiple(int num1, int num2)
{
        return num1 % num2 == 0;    
}

int main()
{

char ch = 'Y';
int num1, num2;
        
        while(ch =='Y') // While ch is equal to Y
        {
                cout << "Enter two numbers(largest first): ";
                cin >> num1; // Getting 1st number 
                cin >> num2; // Getting 2nd number 
                 
                        
                        if(isMultiple(num1, num2)) 
                                
                                cout << num2 << " " << "IS a multiple of " <<" "<< num1<< "\n"; 
                                
                                
                        else
                                cout << num2 << " " << "is NOT a multiple of " <<" "<< num1<< "\n"; 
                                cout << "Would you like to continue? (Y / N): "; 
                                cin >> ch; 
                                ch = toupper(ch); 
                                cout << endl; 
        }
        
return 0;
}

Answer 1

#include <iostream>
using namespace std;

bool isMultiple(int n1, int n2);

int main()
{

char ch = 'Y';
int num1, num2;
  
while(ch =='Y')
{
cout << "Enter two numbers(largest first): ";
cin >> num1; // Getting 1st number
cin >> num2; // Getting 2nd number

  
if(isMultiple(num1, num2))
  
cout << num2 << " " << "IS a multiple of " <<" "<< num1<< "\n";
  
  
else
cout << num2 << " " << "is NOT a multiple of " <<" "<< num1<< "\n";
cout << "Would you like to continue? (Y / N): ";
cin >> ch;
ch = toupper(ch);
cout << endl;
}
  
return 0;
}

bool isMultiple(int n1, int n2)
{
return n1 % n2 == 0;
}