A photon emitted by an excited atom has an energy of 2.5 eV. What is its frequency?
Solution)
Given,
Energy E=2.5*(1.6*10^-19)V= 4*10^-19 V
We know,
E=h*f
Substitute values,
Frequency, f=(4*10^-19)/(6.6*10^-34)= 6.06*10^14 Hz (Ans)
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