Question

Write a MIPS Assembly language program to request a file name from the user, open the file, read the contents, and write it out to the console.

Answer 1

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.data  
    fileName: .asciiz ""      # To store file name
    buffer: .space 1024

    buffer_1: .space 20
    str1:  .asciiz "Please enter the file name"
.text

    la $a0, str1    # Print a prompt asking for the filename
    li $v0, 4
    syscall

    li $v0, 8       # read the  input

    la $a0, buffer_1  # load byte space into address
    li $a1, 20      # allocation of byte space to string

    move $t0, $a0   # save string to t0
    syscall

# Open file for reading

    li   $v0, 13          # system call for open file
    la   $a0, fileName      # name of input file
    li   $a1, 0           # read flag
    li   $a2, 0           
    syscall               # file opened
    move $s0, $v0         # file descriptor saved here


# reading from file just opened

    li   $v0, 14        # reading from file system call
    move $a0, $s0       # file descriptor 
    la   $a1, buffer    # buffer address
    li   $a2,  11       #  predefined buffer length
    syscall             # Trigger reading from file


# Printing File Content
    li  $v0, 4          # system call function for printing a string
    la  $a0, buffer
    syscall             # print the values

    li $v0, 10      # Program Exit call
    syscall

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