CH4 (g) + 2 O2 (g) --> CO2 (g) + 2H2O (g) Δ H = -882 kJ/mol
From the equation above, What is Δ H for the reaction below in kJ/mol.
H2O (g)+ 1/2 CO2 (g) --> O2 (g) + 1/2 CH4 (g)
For the combustion of methane(CH4) CH4 (g) + 2 O2 (g) --> CO2 (g) + 2H2O (g) Δ H = -882 kJ/mol If 250.0 g of CH4 is burned , what is the energy change? ( Answers in scientific notation are entered such as 1.234 e4 )
Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l). Use the series of reaction that follows: 1. C(s)+2H2(g)-> CH4(g), delta H= -74.8 kJ 2. C(s)+O2(g)->CO2(g), delta H= -393.5 kJ 3. 2H2(g)+O2(g)-> 2H2O(g), delta H= -484.0 kJ 4. H2O(l)->H2O(g), delta H= 44.0 kJ
CH4(g) + 2O2(g) CO2(g) + 2H2O(l) ΔHo = -890.5 kJ. What would be the ΔHo for the reaction ½ CH4(g) + O2(g) ½ CO2(g) + H2O(l) What would be the ΔHo for the reaction ½ CH4(g) + O2(g) ½ CO2(g) + H2O(l) What would be the ΔHo for ½ CO2(g) + H2O(l) ½ CH4(g) + O2(g)
Calculate ∆Gº for the reaction, CH4(g)+2O2(g)→CO2(g)+2H2O(g), where ∆Gfº=-50.8 kJ/mol for CH4(g), -394 kJ/mol for CO2(g), and -229 kJ/mol for H2O(g).
Consider the following data.
CH4(g) C(s) + 2 H2(g)
H = +74.8 kJ
C(s) + O2(g)
CO2(g)
H = -393.5 kJ
2 H2(g) +
O2(g) 2 H2O(l)
H = -571.7 kJ
Use Hess's law to calculate H for the reaction below.
CH4(g) + 2 O2(g) CO2(g) + 2 H2O(l)
H = _____ kJ
Calculate ∆Gº for the reaction, CH4(g)+2O2(g)→CO2(g)+2H2O(g), where ∆Gfº=-50.8 kJ/mol for CH4(g), -394 kJ/mol for CO2(g), and -229 kJ/mol for H2O(g): 572 kJ -801 kJ -572 kJ 801 kJ
When 5.00g of methan, CH4, burns 50.2 kJ of heat are produced. CH4(g)+ O2(g) > CO2() +2 H2O a. Is the reaction exothermic or endothermic? b. What is the enthalpy change of the reaction per mole of CH4? In other words, calculate the Change of enthalpy of the reaction in kJ/mol.
Calculate ΔrH for the following reaction: CH4(g)+2O2(g)→CO2(g)+2H2O(l) Use the following reactions and given ΔrH's. CH4(g)+O2(g)→CH2O(g)+H2O(g), ΔrH = -284 kJmol−1 CH2O(g)+O2(g)→CO2(g)+H2O(g), ΔrH = -527 kJmol−1 H2O(l)→H2O(g), ΔrH = 44.0 kJmol−1
Consider the gas phrase reaction shown below: CH4(g) + 2O2 (g) -> CO2(g) + 2H2O (g) Write the rate expression in terms of the rate of appearance of CO2 Rate= ? M/s If the average rate of disapperace of O2 is Δ[O2]/ Δt = -.0400 M/s, calculate the average rate of appearance of CO2 over the same time interval Δ[CO2]/ Δt= ? M/s (Please show all work! thank you!)
The equilibrium constant expression K c for the reaction CH4 (g) + 2O2 (g) <--> CO2 (g) + 2H2O (g) is __________. A. Kc = [CO2][H2O]/[CH4][O2] B. Kc = [CO2][H2O]2/[CH4][O2]2 C. Kc = [CH4][O2]/[CO2][H2O] D. Kc = [CH4][O2]2/[CO2][H2O]2