Researchers presented a study of the wear out failure time of used colored display panels purchased by an outlet store (Mathematical Sciences Colloquium, December 2001). Prior to acquisition, the panels had been used for about one-third of their expected lifetimes. The failure times (in years) for a sample of 50 used panels are reproduced and saved in PANELFAIL file. Find a 95% confidence interval for the true mean failure time of used colored display panels.
FailTime Withdrawal
0.01 No
1.21 No
1.71 No
2.30 No
2.96 No
0.19 No
1.22 No
1.75 No
2.30 No
2.98 No
0.51 No
1.24 No
1.77 No
2.41 No
3.19 No
0.57 No
1.48 No
1.79 No
2.44 No
3.25 No
0.70 No
1.54 No
1.88 No
2.57 No
3.31 No
0.73 No
1.59 No
1.90 No
2.61 No
1.19 No
0.75 No
1.61 No
1.93 No
2.62 No
3.50 No
0.75 No
1.61 No
2.01 No
2.72 No
3.50 No
1.11 No
1.62 No
2.16 No
2.76 No
3.50 No
1.16 Yes
1.62 Yes
2.18 Yes
2.84 Yes
3.50 Yes
Answer:
Given that,
Researchers presented a study of the wear out failure time of used
colored display panels purchased by an outlet store (Mathematical
Sciences Colloquium, December 2001).
Prior to acquisition, the panels had been used for about one-third
of their expected lifetimes.
The failure times (in years) for a sample of 50 used panels are
reproduced and saved in PANELFAIL file.
Find a 95% confidence interval for the true mean failure time of used colored display panel:
We can find the sample mean and sample standard deviation of the given data set using excel function =AVERAGE( ) and =STDEV.S( ) respectively.

Therefore
= 1.935 , S = 0.9287, n = 50
Population standard deviation σ is unknown therefore we use T interval.
Confidence interval is given by,
Lower bound =
– E
Upper bound =
+ E
Margin of error
; t is critical value follows t distribution with degrees of
freedom (d.f ) = n - 1
We have n = 50 and confidence level (c) = 95% or 0.95
d.f = n-1 = 50-1 = 49
α = 1 – c = 1- 0.95 = 0.05
We can find critical value t using excel function =TINV(α,d.f)
=TINV(0.05,49) = 2.01
Therefore ,
Margin of error
=( 2.01
0.9287)/ V50
Margin of error E = 0.2640
Lower bound =
– E = 1.935 - 0.2640 = 1.671
Upper bound =
+ E = 1.935 + 0.2640 = 2.199
95% confidence interval for the true mean failure time of used colored display panels is ( 1.671, 2.199).
Researchers presented a study of the wear out failure time of used colored display panels purchased...
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I've figured out the test statistic is -1.73 and the degrees of
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via the chart (which I'm required to learn how to do).I think the
chart immediately bellow this is the one used to find the p-value.
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I ONLY NEED HELP WITH PART OF PART "B"
I've figured out the test statistic is -1.73 and the degrees of
freedom are 5. However, I'm having a hard time finding the P value
via the chart (which I'm required to learn how to do).I think the
chart immediately bellow this is the one used to find the p-value.
However, I know at least one (or more) of the charts bellow is
what's used. Please let me know which chart...