Question

• Create the class Rectangle. The class will have two int properties, length and width. Create the method printFigure. The method will print a character representation of the rectangle, using an asterisk, *, for each length/width position of the rectangle. Think of the length of the rectangle as the number of rows and the width as the number of columns. Use nested loops to create your solution. If the length was 5 and the width 8, then the printed figure would be:

      *  *  *  *  *  *  *  *
      *  *  *  *  *  *  *  *
      *  *  *  *  *  *  *  *
      *  *  *  *  *  *  *  *
      *  *  *  *  *  *  *  *

• Add a heading of the current length/width position number to the printed figure of the Rectangle. For example:

      1  2  3  4  5  6  7  8   
   
   1  *  *  *  *  *  *  *  *
   2  *  *  *  *  *  *  *  *
   3  *  *  *  *  *  *  *  *
   4  *  *  *  *  *  *  *  *
   5  *  *  *  *  *  *  *  *

Answer 1

import java.util.*;
class Rectangle
{
   public static void main(String [] args)
   {
       int length,width;
       Scanner input=new Scanner(System.in);
       System.out.print("Enter Length of Rectangle:\t");
       length=input.nextInt();
       System.out.print("Enter Width of Rectangle:\t");
       width=input.nextInt();
       printFigure(length,width);
   }
   static void printFigure(int l,int w)
   {
       System.out.println("Without Heading\n");
       for (int i=0;i<l;i++)
       {
           for (int j=0;j<w;j++)
           {
               System.out.print("*\t");
           }
           System.out.println("");
       }
       System.out.println("\n\nWith Heading\n\n");
       for (int i=1;i<=w;i++)
           System.out.print("\t"+i);
       System.out.println("");
       for (int i=0;i<l;i++)
       {
           System.out.print(i+1);
           for (int j=0;j<w;j++)
           {
               System.out.print("\t*");
           }
           System.out.println("");
       }
   }
}