An electron has de Broglie wavelength 2.81×10−10 m Determine the kinetic energy Ke of the electron. Express your answer in joules to three significant figures. THE ANSWER IS NOT 1.29*10^4
Kinetic energy = p^2 / 2m
p is momentum and equal to h/
h is plank's constant , 6.62×10^-34 kg m^2/s
is de Broglie wavelength of electron
m is mass of electron , 9.1×10^-31 kg
Kinetic energy = h^2 / ^2 2 m
= 6.62^2×10^-68 / 2.81^2×10-20 * 2*9.1×10-31
= 3.05×10^-18 J
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