When testing the effectiveness of a medicine, 57.3% of those taking the medicine noticed an improvement...
When testing the effectiveness of a medicine, 57.3% of those taking the medicine noticed an improvement in their health. For a random sample of 392 individuals, find the mean, variance, and standard deviation for the number of individuals who will not notice an improvement in their health. Show your work to receive credit.
Homework Answers
Solution :
Given that,
p = 0.573
q = 1 - p =1-0.573=0.427
n = 392
Mean = 
= n * p = 392*0.573=224.616
variance 
2= n * p * q = 392*0.573*0.427=95.9110
Standard deviation =
= 
n * p * q = 392*0.573*0.427=9.7934
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