80g of propanone was heated from 25.5 degrees Celsius to 63.4 degrees Celsius. How much energy...
80g of propanone was heated from 25.5 degrees Celsius to 63.4 degrees Celsius. How much energy was transferred to the propanone during heating? Specific heat of propanone is 2.13J/g
Homework Answers
Q= m×specific heat ×(T2-T1) now subtitue values then Q= (80g) × (2.13J/g)× (63.4-25.5) K on solving above we get energy transferred to propane during heating (Q)= 6458.16 J OR Q= 6.45816KJ (Kilojoules)
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80g of propanone was heated from 25.5 degrees Celsius to 63.4
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