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In the game of​ roulette, a player can place a ​$10bet on the number 25and have...

In the game of​ roulette, a player can place a

​$10bet on the number 25and have a 1/38probability of winning. If the metal ball lands on

25​, the player gets to keep the $10

paid to play the game and the player is awarded an additional

​$350.Otherwise, the player is awarded nothing and the casino takes the​ player's

​$10.

Find the expected value​ E(x) to the player for one play of the game. If x is the gain to a player in a game of​ chance, then​ E(x) is usually negative. This value gives the average amount per game the player can expect to lose.

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Answer #1

TOPIC:Expected gain of the game of chance.

Hence,The expected gain= - $0.5263.

So,the player can expect to loss $0.5263,on average.(ANSWER)

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