The variable Z has a standard normal distribution. The probability P(-1.27 < Z < 2.19) is:
| a. |
0.9852 |
|
| b. |
0.1020 |
|
| c. |
0.8830 |
|
| d. |
0.8832 |
QUESTION 6
The probability P(-1.45<= Z <= 0) is:
| a. |
0.9929 |
|
| b. |
0.0735 |
|
| c. |
0.4265 |
|
| d. |
0.5071 |
3
If P(Z > z) = 0.7881, then the z-score is:
| a. |
0.80 |
|
| b. |
-0.80 |
|
| c. |
0.58 |
|
| d. |
-0.58 |
The variable Z has a standard normal distribution. The probability P(-1.27 < Z < 2.19) is:...
Find the following z values for the standard normal variable Z. (You may find it useful to reference the z table. Negative values should be indicated by a minus sign. Round your answers to3 decimal places.) a. P(Z s z)-0.1020 b. P(z s Z s 0)-0.1772 c. P(Z> z) 0.9929 d. P(0.40 sZsz)- 0.3368
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Find the following probabilities for a standard normal variable, Z 1) P(Z<-1.27) 2) P(-2.03<Z<3.49) 3) P(Z>1.74) 4)P(Z<0.17) B. Find z if we know that the area to the left of z (under the normal curve) is 0.9265.
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