The change in internal energy for the combustion of 1.0 mol of octane at a pressure...

Question

Question

The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kJ

If the change in enthalpy is -5074.3 kJ, how much work is done during the combustion?

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Answer 1

Answer #1

Sol .

As change in internal energy = deltaU = - 5084.1 KJ

change in enthalpy = deltaH = - 5074.3 KJ

So , Work done = deltaU - deltaH

= - 5084.1 - ( - 5074.3 )

= - 5084.1 + 5074.3

= - 9.8 KJ

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Answer 2

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