Suppose that the efficacy of a certain drug is 0.63. Consider
the sampling distribution (sample size n = 143) for the proportion
of patients cured by this drug.
What is the mean of this distribution?
What is the standard error of this distribution?
mean of the proportion = 0.63
standard error of proportion = sqrt(p*(1-p)/n)
= sqrt(0.63*(1-0.63)/143)
= 0.0404
Suppose that the efficacy of a certain drug is 0.63. Consider the sampling distribution (sample size...
Suppose that the efficacy of a certain drug is 0.63. Consider the sampling distribution (sample size n = 108) for the proportion of patients cured by this drug. What is the mean of this distribution?Answer:______ (Enter your answer as a number accurate to 2 decimal places.) What is the standard deviation of this sampling distribution (i.e., the standard error)? Answer:______(Enter your answer as a number accurate to 3 decimal places.)
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Verizon LTE1 :46 PM 65% Done 35 of 41 Question 12 Score on last try. 0.5 of 1 pts. See Details for more Try a similar question You can retry this question below Suppose that the efficacy of a certain drug is 0.55. Consider the sampling distribution (sample sizen = 153) for the proportion of patients cured by this drug. What is the mean of this distribution? What is the standard error of this distribution? Question Help: Message instructor Submit...
Consider a sampling distribution with p=0.09 and samples of size n each. Using the appropriate formulas, find the mean and the standard deviation of the sampling distribution of the sample proportion. a. For a random sample of size n=4000. b. For a random sample of size n=1000. c. For a random sample of size n=250.
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