An office manager claims that the amount of time individual employees spend replying to emails each...
An office manager claims that the amount of time individual employees spend replying to emails each hour has a mean of 14 minutes and a standard deviation of 2.3 minutes, A particular employee was observed for one hour and the amount of time spent replying to emails was 11 minutes, Calculate the z-score for this time spent replying to emails. Round to two decimal places.
Homework Answers
This is a normal distribution question with
P(z = 11.0)=?
The z-score at x = 11.0 is,
z = -1.3043
Please hit thumbs up if the answer helped you
Add Answer to:
An office manager claims that the amount of time individual
employees spend replying to emails each...
An employee group for a retailer claims that the mean time spent by employees on a...
An employee group for a retailer claims that the mean time spent by employees on a personal phone call is less than 10 minutes per day. A random sample of 25 employees is taken and showed a mean of 9.2 minutes and a standard deviation of 2 minutes. Test the claim with a 5% significance level the time is less than 10 minutes.
StatChapter02: Problem 11 (1 point) The amount of time students spend on a particular homework assignment...
StatChapter02: Problem 11 (1 point) The amount of time students spend on a particular homework assignment has a mean of 34.03 A student spends 47 minutes on this assignment. The z-score for this student is minutes and standard deviation of 5.2 minutes. You have unlimiteh Page generated at 01/19/2019 at 10 38pm EST
Last year, during an investigation of the time spent reading emails on a daily basis, researchers...
Last year, during an investigation of the time spent reading emails on a daily basis, researchers found that on Monday the average time was 50 minutes. Office workers claim that with the increased spam and junk mail, this time has now increased. To conduct a test, a sample of 25 employees is selected, with the following results: sample mean = 51.05 minutes and sample standard deviation = 4.42 minutes. Test the hypothesis that the time has increased from last year...
A facilities manager at a university reads in a research report that the mean amount of...
A facilities manager at a university reads in a research report that the mean amount of time spent in the shower by an adult is 5 minutes. He decides to collect data to see if the mean amount of time that college students spend in the shower is significantly different from 5 minutes. In a sample of 11 students, he found the average time was 4.52 minutes and the standard deviation was 0.75 minutes. Using this sample information, conduct the...
The amount of time that people spend at Grover Hot Springs is normally distributed with a...
The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 60 minutes and a standard deviation of 17 minutes. Suppose one person at the hot springs is randomly chosen. Let X = the amount of time that person spent at Grover Hot Springs . Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N( , ) b. Find the probability that a randomly...
In order to estimate the mean amount of time computer users spend on the internet each...
In order to estimate the mean amount of time computer users spend on the internet each month, how many computer users must be surveyed in order to be 90% confident that your sample mean is within 11 minutes of the population mean? Assume that the standard deviation of the population of monthly time spent on the internet is 208 min. What is a major obstacle to getting a good estimate of the population mean? Use technology to find the estimated...
4. You want to estimate the amount of time college students spend on facebook each month....
4. You want to estimate the amount of time college students spend on facebook each month. How many college students must be surveyed in order to be 95% confident that your sample mean is 15 minutes of the population mean? Based on results from a prior Nielsen survey, assume that the standard deviation of the population of monthly time spent on facebook is 210 minutes.
This Test: 46 pts possible 4 30 of 46 (0 complete) This Question: 1 pt A radio station claims that the amount of advertising per hour of broadcast time has an average of 17 minutes and a standard dev...
This Test: 46 pts possible 4 30 of 46 (0 complete) This Question: 1 pt A radio station claims that the amount of advertising per hour of broadcast time has an average of 17 minutes and a standard deviation equal to 1.1 minutes. You listen to the radio station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 15 minutes Calculate the z score for this amount of advertising...
A company claims that the time their customers spend waiting in line for service is normally...
A company claims that the time their customers spend waiting in line for service is normally distributed with a mean of 21.4 minutes and a standard deviation of 7.2 minutes. Approximately 10% of the customers can expect to wait as long as how many minutes for service? (with steps please)
In order to estimate the mean amount of time computer users spend on the internet each...
In order to estimate the mean amount of time computer users spend on the internet each month, how many computer users must be surveyed in order to be 95% confident that your sample mean is within 11 minutes of the population mean? Assume that the standard deviation of the population of monthly time spent on the internet is 200 min. What is a major obstacle to getting a good estimate of the population mean? Use technology to find the estimated...
An employee group for a retailer claims that the mean time spent by employees on a personal phone call is less than 10 minutes per day. A random sample of 25 employees is taken and showed a mean of 9.2 minutes and a standard deviation of 2 minutes. Test the claim with a 5% significance level the time is less than 10 minutes.
StatChapter02: Problem 11 (1 point) The amount of time students spend on a particular homework assignment has a mean of 34.03 A student spends 47 minutes on this assignment. The z-score for this student is minutes and standard deviation of 5.2 minutes. You have unlimiteh Page generated at 01/19/2019 at 10 38pm EST
This Test: 46 pts possible 4 30 of 46 (0 complete) This Question: 1 pt A radio station claims that the amount of advertising per hour of broadcast time has an average of 17 minutes and a standard deviation equal to 1.1 minutes. You listen to the radio station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 15 minutes Calculate the z score for this amount of advertising...
Most questions answered within 3 hours.
-
Where is the error in this code sequence?
String s1 = "Hello";
String s2 = "ello";...
asked 11 months ago -
Financial data for Joel de Paris, Inc., for last year
follow:
Joel de Paris, Inc.
Balance...
asked 11 months ago -
Consider this reaction:
Al2(SO4)3 (aq)+ BaCl3
(aq) Al2Cl6 (aq)- +
3BaSO4(s) . What is the...
asked 11 months ago -
Suppose that Savneet is considering increasing her
recent random sample from 20 car rentals to 40...
asked 11 months ago -
Trucks arrive at an unloading terminal at an average rate of 120
per hour.
Trucks arrive...
asked 11 months ago -
Why are methanol and ethanol completely soluble in water while
octanol is not very little soluble....
asked 11 months ago -
A facilities manager at a university reads in a research report
that the mean amount of...
asked 11 months ago -
When the CuSO4 is rehydrated by adding water to the anhydrous
compound, is this an endothermic...
asked 11 months ago -
A ray of sunlight is passing from diamond into crown glass; the
angle of incidence is...
asked 11 months ago -
A block of mass 0.249 kg is placed on top of a light, vertical
spring of...
asked 11 months ago -
how do the kidneys compensate in the presences of acidosis
a) trigger hyperventilate
b) reserve acid...
asked 11 months ago -
Question 501 pts
The rental rate of capital to the firm increases. Which of the
following...
asked 11 months ago