The regression equation is y = 47.17 - 9.74 x1 + 0.428 x2 + 18.2 x3....
The regression equation is y = 47.17 - 9.74 x1 + 0.428 x2 + 18.2 x3. If x1=14.5, x2=220, x3=5, the predicted value of y is? A) 373.56 B) 91.1 C) 47.17 D) 0
Homework Answers
The regression equation is:
y = 47.17 - (9.74)x1 + (0.428)x2 + (18.2)x3
Putting the values, x1=14.5, x2=220 and x3=5, we get,
y = 47.17 - (9.74)(14.5) + (0.428)(220) + (18.2)(5) = 91.1
Hence option B is the correct option.
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The regression equation is y = 47.17 - 9.74 x1 + 0.428 x2 + 18.2
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