Let X be a random variable with a normal distribution having a mean of 30 and...
Homework Answers
Probability that X is greater than 50 = P(X>50) = 1- P(X<50) = 1-P(z<1.25) = 1- 0.8944 = 0.1056
where , Z score = ( X - mean)/std deviation = (50 - 30)/16
= 20/16 = 5/4 = 1.25
Correct option is A)
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