Question

A ray of light travels from air into glass ( n glass =1.33 ). The incident angle ( θi ) is 23 ∘ . Hints: n i sin( θ i )= n r sin( θ r ) nisin(θi)=nrsin(θr) If θ i = θ critical θi=θcritical then θ r = 90 ∘ θr=90∘ n air =1.00 nair=1.00 What is the refracted angle inside the glass in degrees? θ r θr = ∘ If the light ray instead travels from the glass into the air at an incident angle of 12.08∘ , at what angle will the light ray exit the glass? θr = ∘ What is the critical angle for the glass to air interface? θcritical = ∘

Answer 1