Multiple-choice questions each have four possible answers left parenthesis a comma b comma c comma d right parenthesis, one of which is correct. Assume that you guess the answers to three such questions. a. Use the multiplication rule to find P(WCC), where C denotes a correct answer and W denotes a wrong answer. P(WCC)equals nothing (Type an exact answer.) b. Beginning with WCC, make a complete list of the different possible arrangements of two correct answers and one wrong answer, then find the probability for each entry in the list. P(WCC)minussee above P(CCW)equals nothing P(CWC)equals nothing (Type exact answers.) c. Based on the preceding results, what is the probability of getting exactly two correct answers when three guesses are made? nothing (Type an exact answer.)
Answer:
P(C) = 1/4 and P(W) = 3/4
a) P(WCC) = (1/4)*(3/4)*(1/4) = 3/64 = 0.046875
b) P(WCC) = 3/64 = 0.046875
P(CWC) = 3/64 = 0.046875
c) P(Two correct answers when three guesses are made) = 3*3/64 = 9/64 = 0.140625
Multiple-choice questions each have four possible answers left parenthesis a comma b comma c comma d...
Unsure of my answer for c.
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Multiple-choice questions each have five possible answers (a, b, c, d, e), one of which is correct. Assume that you guess the answers to three such questions. a. Use the multiplication rule to find P(CCW), where C denotes a correct answer and W denotes a wrong answer. P(CCW)=(Type an exact answer.) b. Beginning with CCW, make a complete list of the different possible arrangements of two correct answers and one wrong answer, then find the probability for each entry in the list. P(CCW)- see...
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