Question

steady-state creep

Steady-state creep data takenfor an iron at a stress level of 140 MPa (20,000 psi) are givenhere:

εsT(K)

6.6*10-41090

8.8*10-21200

If it is known that the valueof the stress exponent n for this alloy is 8.5, compute thesteady-state creep rate at 1300 K and a stress level of 83 MPa(12,000psi).

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Answer #1

Consider the relation for the steady state creep rate as follows:

…… (1)

Apply natural laogarithm for the equation.

…… (2)

Consider the two differnet temperatures and the two steady state creep rate values, and hence write the equation (2) as follows:

…… (3)

…… (4)

Subtract equations (3) from equation (4).

…… (5)

Substitute for , for , for ,for, and for R in equation (5).

Substiute for , 8.5 for n, for , for , and for R, 140 MPa for in equation (2).

Calculate the steady state creep rate.

Consider equation (1).

Substiute for , for , for R , 83 MPa for , 8.5 for n.

Therefore, the steady state creep rate at 1300 K and a stress level of 83 MPa is .

> Ln(k_2)=8.558 does not equate to k_2=61.174 s^(-1) therefore the solution is wrong

ximad767473 Sat, Mar 19, 2022 9:12 PM

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