Steady-state creep data takenfor an iron at a stress level of 140 MPa (20,000 psi) are givenhere:
εsT(K)
6.6*10-41090
8.8*10-21200
If it is known that the valueof the stress exponent n for this alloy is 8.5, compute thesteady-state creep rate at 1300 K and a stress level of 83 MPa(12,000psi).Consider the relation for the steady state creep rate as follows:
…… (1)
Apply natural laogarithm for the equation.
…… (2)
Consider the two differnet temperatures
and the two steady state creep rate values
, and hence write the equation (2) as follows:
…… (3)
…… (4)
Subtract equations (3) from equation (4).
…… (5)
Substitute
for
,
for
,
for
,
for
, and
for R in equation (5).
Substiute
for
, 8.5 for n,
for
,
for
, and
for R, 140 MPa for
in equation (2).
Calculate the steady state creep rate.
Consider equation (1).
Substiute
for
,
for
,
for R , 83 MPa for
, 8.5 for n.
Therefore, the steady state creep rate at 1300 K and a stress level of 83 MPa is
.
Steady-state creep data taken for an aluminum at 260°C (533K) are given as follows: creep rate (1/h) σ (MPa) 2.00E-04 3 3.65 25 determine the K1 and n constants and plot the dependence of creep rate from applied stress in a range from 1 to 60 MPa.
Animated Figure 9.41 shows a plot of the logarithm stress versus
the Larson-Miller parameter for an S-590 alloy. A component made of
this alloy must have a creep rupture lifetime of at least 20 days
at 750°C (1023 K). Compute the maximum allowable stress level in
MPa.
Larson-Miller parameter 12- 103 (R-h) 103 T(20 + log ir)("R-h) Larson-Miller parameter 2.2- 10s (K-h) Stress 6.9 MPA Stress 1 105 psi 25 30 35 4045 50 1000 100 100 CD 10 9...
Animated Figure 8.34 shows a plot of the logarithm stress versus the Larson Miller parameter for an 5-590 alloy. A component made of this alloy must have a creep rupture lifetime of at least 20 days at 600°C (873 K). Compute the maximum allowable stress level MPa (The tolerance is +/- 10%.] Click if you would like to Show Work for this question: Open Show Work
Chapter 08, Problem 8.05 amated Eigurea4 shows a plt of the lagarithm stress versus the Larson-Miller parameter for an S590 alcy. A cormponent made of this alloy must have a creep rupture lfetime of at least 20 days at 750c (1023 maximum allawable stress level. MPa me tolerance is 4- 10%. Click if you would like to Show Work for this question: Open Shaw Wark Larson-Miller parameter 12-103 (R-h) Larson-Miller parameter 2.2 103 (K-h) Stress = 6.9 MPA Stress =...
Can someone help me with this materials problem?
Problem 7.23 Your answer is partially correct. Try again. Consider the brass alloy for which the stress-strain behavior is shown in the Animated Figure 7.12. A cylindrical specimen of this material 10.1 mm (0.3976 in.) in diameter and 98.8 mm (3.890 in.) long is pulled in tension with a force of 10200 N (2293 lbr). If it ls known that this alloy has a value for Polsson's ratio of 0.35, compute (a)...
Problem set 4
The steady-state per capita consumption is written as
c=Aka -(n+)k
where c is the steady-state per capita consumption.
A: productivity
k: per capita capital stock
δ: capital depreciation rate
n: population growth rate
Question : Compute the Golden rule kGR that maximizes
the steady-state per capita consumption level?
The fatigue data for a ductile cast iron are given as follows: (7 pts Stress Amplitude IMPa (ksi 248 (36.0) 236 (34.2) 224 (32.5 213 (30.9) 201 (29.1) 93 (28.0) 193 (28.0 193 (28.0) Cycles to Failure I x 10 3 x 10 1 x 10 I x 107 3 x 107 3 x 10 a) Make an S-N plot (stress amplitude versus logarithm cycles to failure) using these data. b) What is the fatigue limit for this alloy? (c)...
1. Draw a schematic stress-strain diagram for steel. Make sure you mark all the important points and regions on it. Provide a one-two sentence explanation for each point and region along the diagram. 2. A cylindrical specimen of a nickel alloy having an elastic modulus of 207 GPa (30 x 10* psi) and an original diameter of 10.2 mm (0.40 In.) will experience only elastic deformation when a tensile load of 8900 N (2000 Ibe) is applied. Compute the maximum length...
3. (Steady state in the Solow model) Consider two economies identical in everything except the production function. Economy 1 has a production function F(K, L) KL,economy 2 has a production function G(K, L) aK1 - a)L. For both economies capital grows according to (1). a) Write output per worker as a function of capital per worker for both economies. b) Compute the steady state value of capital per worker for both these economies or, if it does not exist, show...
3. (Steady state in the Solow model) Consider two economies identical in everything except the production function. Economy 1 has a production function \(F(K, L)=K^{\alpha} L^{1-\alpha}\), economy 2 has a production function \(G(K, L)=\alpha K+(1-\alpha) L\). For both economies capital grows according to (1).a) Write output per worker as a function of capital per worker for both economies.b) Compute the steady state value of capital per worker for both these economies or, if it does not exist, show graphically that...
> Ln(k_2)=8.558 does not equate to k_2=61.174 s^(-1) therefore the solution is wrong
ximad767473 Sat, Mar 19, 2022 9:12 PM