At standard temperature and pressure (0 ∘C and 1.00 atm ), 1.00 mol of an ideal...

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At standard temperature and pressure (0 ∘C and 1.00 atm ), 1.00 mol of an ideal...

At standard temperature and pressure (0 ∘C and 1.00 atm ), 1.00 mol of an ideal gas occupies a volume of 22.4 L. What volume would the same amount of gas occupy at the same pressure and 65 ∘C?

Express your answer numerically in liters.

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Answer 1

Answer #1

We can apply PV/T = constant

1.00atm×22.4L/273.15K = 1.00atm×V/(273.15+65)K

V = 27.73 L

Volume = 22.7 L ( Answer)

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Answer 2

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