The amount of power dissipated in a 10 ohm resistor with 1 amp and 10 volts is _____________.
We know power dissipated by a resistor is
P = IV
P= I^(2)R
Here I = 1A, R=10ohm, and V=10volts
So, the power dissipated will be from above relations and given values:
P = 1A×10V = 10W
Or P = 1^(2)×10 = 10W
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