Let three capacitor C1,C2 and C3 are conneted in series then
Equivalent capacitor is given by
1/Ceq=1/C1+1/C2+1/C3
So
Ceq=(C1C2C3)/(C1C2+C1C3+C2C3)
If
One Capacitor C3 is removed
then
Ceq=C1C2/(C1+C2)
Then Equivalent capacitance will increase.
Three capacitors are connected in series. If one capacitor is removed, the equivalent capacitance increases?
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1.How can one increase the equivalent capacitance of a network of capacitors by use of an extra capacitor? 2.When a capacitor is connected to a source, is there a noticable time delay for charging the capacitor fully? If so, what does the delay depend on? 3.How does one determine the equivalent capacitance of a network of capacitors in series? 4.How does one determine the equivalent capacitance of a network of capacitors in parallel?
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What is the equivalent capacitance for the following three capacitors connected in series: C1 = 70 uF, C2 = 10 pF, and C3 = 70 UF ? F Submit Answer Tries 0/2 e Post Discussion C1 C2 C3 What is the equivalent capacitance for the following three capacitors connected in parallel: C1 = 10 pF, C2 = 30 pF, and C3 = 60 uF ? MF Submit Answer Tries 0/2