Suppose the American Kennel Club estimates that 36% of households in U.S. have a Pembroke Welsh Corgi. A random sample of 400 households is taken. What is the probability the sampling error is 5% or less?
Ans:
n=400
z(0.31)=(0.31-0.36)/SQRT(0.36*(1-0.36)/400)=-2.083
z(0.41)=(0.41-0.36)/SQRT(0.36*(1-0.36)/400)=2.083
P(0.31<p-hat<0.41)=P(-2.083<z<2.083)=P(z<2.083)-P(z<-2.083)
=0.9814-0.0186=0.9628
Suppose the American Kennel Club estimates that 36% of households in U.S. have a Pembroke Welsh...
Suppose the American Kennel Club estimates that 36% of households in U.S. have a pembroke welsh corgi. A random sample of 400 households is taken. A) What is the probability that the sample proportion is more than 40%? B) what is the probability that the sample proportion is within .04 of P? C) what is the probability the sampling error is 5% or less?
A.) Suppose the American Kennel Club estimates that 36% of households in U.S. have a Pembroke Welsh Corgi. A random sample of 400 households is taken. What is the probability the sample proportion is more than 40%? B.) Suppose the American Kennel Club estimates that 36% of households in U.S. have a Pembroke Welsh Corgi. A random sample of 400 householdz is taken. What is the probability the sample proportion is within .03 of P?
Suppose the American Kennel Club estimates that 36% of households in U.S. have a Pembroke Welsh Corgi. A random sample of 400 households is taken. What is the probability the sample proportion is within .03 of P? Question 14 options: 1) .9044 2) 1 3) 0 4) .7887
Suppose the American Kennel Club estimates that 36% of households in U.S. have a Pembroke Welsh Corgi. A random sample of 400 households is taken. What is the probability the sample proportion is within .04 of P? Question 14 options: 1) 1 2) .9044 3) 0 4) .7887 Previous PageNext Page
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