HomeworkLib
Question

Tom has a mass of 75 kg and Sally has a mass of 51.6 kg. Tom...

Tom has a mass of 75 kg and Sally has a mass of 51.6 kg. Tom and Sally are standing 39.9 m apart on a massless dance floor. Sally looks up and she sees Tom. She feels an attraction. If the attraction is gravitation, find its magnitude. Assume both can be replaced by point masses and that the gravitational constant is 6.67259 × 10−11 N · m2 /kg2 . Answer in units of N.

science   physics   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

0 0
Add a comment
Know the answer?
Add Answer to:
Tom has a mass of 75 kg and Sally has a mass of 51.6 kg. Tom...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • a. Two 700-kg masses (1543 lb) are separated by a distance of 33 m. Using Newton’s...

    a. Two 700-kg masses (1543 lb) are separated by a distance of 33 m. Using Newton’s law of gravitation, find the magnitude of the gravitational force exerted by one mass on the other. (Use G = 6.67 × 10-11 N·m2/kg2.) (Round the final answer to four decimal places.) The magnitude of the gravitational force exerted by one mass on the other is ___________ × 10–9 N. b. Two masses are attracted by a gravitational force of 0.36 N. What will...

  • A 1.3 kg mass weighs 11.18 N on the surface of a planet similar to Earth....

    A 1.3 kg mass weighs 11.18 N on the surface of a planet similar to Earth. The radius of this planet is roughly 7.3 × 106 m. Calculate the mass of of this planet. The value of the universal gravitational constant is 6.67259 × 10−11 N · m2 /kg2 . Answer in units of kg. The answer for the question #1 above is 6.868307509 x 10^24 I just need the answer to the next problem Calculate the average density of...

  • A heavier mass m1 and a lighter mass m2 are 19.5 cm apart and experience a...

    A heavier mass m1 and a lighter mass m2 are 19.5 cm apart and experience a gravitational force of attraction that is 8.90 x 10-9 N in magnitude. The two masses have a combined value of 5.45 kg. Determine the value of each individual mass. m₂ = kg m₂ = kg

  • A heavier mass m1 and a lighter mass m2 are 18.5 cm apart and experience a...

    A heavier mass m1 and a lighter mass m2 are 18.5 cm apart and experience a gravitational force of attraction that is 9.00 10-9 N in magnitude. The two masses have a combined value of 5.45 kg. Determine the value of each individual mass.

  • A heavier mass m1 and a lighter mass m2 are 17.0 cm apart and experience a...

    A heavier mass m1 and a lighter mass m2 are 17.0 cm apart and experience a gravitational force of attraction that is 9.60 10-9 N in magnitude. The two masses have a combined value of 5.3 kg. Determine the value of each individual mass.

  • Three identical masses of 570 kg each are placed on the x axis. One mass is at x1 = -150 cm , one is...

    Three identical masses of 570 kg each are placed on the x axis. One mass is at x1 = -150 cm , one is at the origin, and one is at x2 = 350 cm . Part A What is the magnitude of the net gravitational force Fgrav on the mass at the origin due to the other two masses? Take the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 . Express your answer in Newtons.

  • Three identical masses of 570 kg each are placed on the x axis. One mass is at x1 = -150 cm , one is...

    Three identical masses of 570 kg each are placed on the x axis. One mass is at x1 = -150 cm , one is at the origin, and one is at x2 = 350 cm . Part A What is the magnitude of the net gravitational force Fgrav on the mass at the origin due to the other two masses? Take the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 . Express your answer in Newtons.

  • A satellite of mass 350 kg is launched from a site on the Equator into an...

    A satellite of mass 350 kg is launched from a site on the Equator into an orbit at 317 km above Earth’s surface. If the orbit is circular, what is the satellite’s speed in orbit? The gravitational constant is 6.67259 × 10−11 N · m2 /kg2 , the mass of the earth is 5.98 × 1024 kg and its radius is 6.37 × 106 m . Answer in units of m/s. 018 (part 2 of 3) 10.0 points What is...

  • A satellite used in a cellular telephone network has a mass of 2380 kg and is...

    A satellite used in a cellular telephone network has a mass of 2380 kg and is in a circular orbit at a height of 850 km above the surface of the earth. Part A What is the gravitational force Fgrav on the satellite? Take the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , the mass of the earth to be me = 5.97×1024 kg , and the radius of the Earth to be re = 6.38×106 m

  • The mass of a certain neutron star is 9 × 1030 kg (4.5 solar masses) and...

    The mass of a certain neutron star is 9 × 1030 kg (4.5 solar masses) and its radius is 5500 m. What is the acceleration of gravity at the surface of this condensed, burned-out star? The value of the universal gravitational constant is 6.67 × 10−11 N · m2 /kg2 . Answer in units of m/s 2 .

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT