1.) If 15.0 mL of 3.60 M HCl (aq) are added to 10.0 mL of water,...

Question

Question

1.) If 15.0 mL of 3.60 M HCl (aq) are added to 10.0 mL of water, what is the concentration of the resulting solution?

2.) How many mL of water must be added to 25.0 mL of a 0.500 M NaCl solution to result in a solution that is 0.200 M NaCl?

3.) The net ionic equation for the reaction of aqueous solutions of sodium chloride and silver nitrate is...?

4.) How many mL of a 0.500 M sodium chloride solution contains 0.100 moles of NaCl?

5.) The net ionic equation for the reaction of aqueous solutions of sodium sulfate and aluminum chloride is...?

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Answer 1

Answer #1

Ans 1 :

Initial volume V1 = 15.0 mL

final volume V2 = 15.0 mL + 10.0 mL = 25.0 mL

initial concentration M1 = 3.60 M

using relation M1V1 = M2V2

3.60 M x 15.0 mL = M2 x 25.0 mL

M2 = 2.16 M

Answer 2

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